If A = [aij] is a square matrix of even order such that aij = i2 – j2, then

aij = i2 – j2


a11 = 12 – 12 = 0


a12 = 12 – 22 = -3


a21 = 22 – 12 = 3


a22 = 22 – 22 = 0





So, AT = -A


|A| = 0(0) – (-3)(3) = 0 + 9 = 9 ≠ 0


So, none of these.


Option (D) is the answer.

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