If A = [aij] is a square matrix of even order such that aij = i2 – j2, then
aij = i2 – j2
a11 = 12 – 12 = 0
a12 = 12 – 22 = -3
a21 = 22 – 12 = 3
a22 = 22 – 22 = 0
So, AT = -A
|A| = 0(0) – (-3)(3) = 0 + 9 = 9 ≠ 0
So, none of these.
Option (D) is the answer.