We are given that,

A and B are square matrices of order 3.

|A| = -1, |B| = 3

We need to find the value of |3AB|.

By property of determinant,

|KA| = Kⁿ|A|

If A is of n^th order.

If order of A = 3 × 3

And order of B = 3 × 3

⇒ Order of AB = 3 × 3 [∵, Number of columns in A = Number of rows in B]

We can write,

|3AB| = 3³|AB| [∵, Order of AB = 3 × 3]

Now, |AB| = |A||B|.

⇒ |3AB| = 27|A||B|

Putting |A| = -1 and |B| = 3, we get

⇒ |3AB| = 27 × -1 × 3

⇒ |3AB| = -81

Thus, the value of |3AB| = -81.