Choose the correct answer.
If f(x) = a |sinx| + b e|x| + c|x3| and if f(x) is differentiable at x = 0, then
Given that f(x) = a |sinx| + b e|x| + c|x3| and f(x) is differentiable at x = 0.
⇒ LHD = RHD at x = 0.
By L’Hospital Rule,
⇒ -(a+b) = a+b
⇒ -2(a+b) = 0
⇒ a + b =0
This is the value for all c € R.
Hence, option B is correct.