Given that the function f(x) given by f(x) = |x – 3| cos x is differential then

LHD at x =3,

RHD at x =3,

∵ LHD ≠ RHD

∴ f(x) is not differentiable at x = 3 but since it is a product of modular and cosine function, it is differentiable at all other points.

Hence, option B is correct.