Choose the correct alternative in the following:
If f(x) = tan–1
0 ≤ x ≤ π/2, then f’ (π/6) is
∵ sin2x = 2 sin x cos x
⇒ sin x = 2 sin x/2 cos x/2
∵ sin2x/2 + cos2x/2 = 1
Dividing by cos x/2 we get
Taking – common
∵ 0 ≤ x ≤ π/2
1
Choose the correct alternative in the following:
If f(x) = tan–1 0 ≤ x ≤ π/2, then f’ (π/6) is
∵ sin2x = 2 sin x cos x
⇒ sin x = 2 sin x/2 cos x/2
∵ sin2x/2 + cos2x/2 = 1
Dividing by cos x/2 we get
Taking – common
∵ 0 ≤ x ≤ π/2