If y = a xn+1 + bx–n and 
then write the value of λ.
Given:
y=axn+1 +bx-n
λy=n(n+1)a xn-1+2 +n(n+1)bx-n-2+2
λy=n(n+1)[a x^(n+1)+bx^(-n)]
λy=n(n+1)
λ=n(n+1)
1
If y = a xn+1 + bx–n and then write the value of λ.
Given:
y=axn+1 +bx-n
λy=n(n+1)a xn-1+2 +n(n+1)bx-n-2+2
λy=n(n+1)[a x^(n+1)+bx^(-n)]
λy=n(n+1)
λ=n(n+1)