If x = a cos nt – b sin nt and 
then find the value of λ.
Given:
y=a cos nt-b sin nt
λy= -n2 (a cos nt-b sin nt )
λy= - n2 y
λ= -n2
1
If x = a cos nt – b sin nt and then find the value of λ.
Given:
y=a cos nt-b sin nt
λy= -n2 (a cos nt-b sin nt )
λy= - n2 y
λ= -n2