Mark the correct alternative in the following:
The distance moved by the particle in time is given by x = t3 – 12t2 + 6t + 8. At the instant when its acceleration is zero, the velocity is
If we are given the distance travelled(x) as a function of time, we can calculate velocity(v) and acceleration(a) by
and a
x(t)= t3 – 12t2 + 6t + 8
differentiating w.r.t. time, we get
Differentiating again w.r.t. time, we get
a
Given that a=0 ⇒ 6t-24=0 or t=4 units
v(4)=3×42 -24×4+6 =-42