Mark the correct alternative in the following:

If s = t3 – 4t2 + 5 describes the motion of a particle, then its velocity when the acceleration vanishes, is


If we are given the distance travelled(s) as a function of time, we can calculate velocity(v) and acceleration(a) by

and a


s(t)= t3 – 4t2 + 5


differentiating w.r.t. time, we get



Differentiating again w.r.t. time, we get


a


Given that a=0 6t-8=0 or units


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