Mark the correct alternative in the following:

If there is an error of 2% in measuring the length of a simple pendulum, then percentage error in its period is:


given (ΔL/L)×100 = 2 (if we let the length of pendulum is L)

we all know the formula of period of a pendulum is T=2π×√(l/g)


By the formula of approximation in derivation ,we get-




=1%

1