Mark the correct alternative in the following:
A sphere of radius 100 mm shrinks to radius 98 mm, then the approximate decrease in its volume is
we know that volume of sphere = v = (4/3)×πr3 (r is radius of sphere)
r = 100mm
=4πr2Δr
Δr = (98-100)
=-2
Δv=4π(100)2×(-2)
Δv = - 80,000π mm3ans
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