Mark the correct alternative in the following:
If the ratio of base radius and height of a cone is 1 : 2 and percentage error in radius is λ%, then the error in its volume is:
given that the radius is half then the height of the cone so
Let h = 2r (where r is radius and h is height of the cone)
Volume of the cone = v
(because h = 2r )
Δv = 2πr2Δr
So finally ,
= 3×λ
= 3λ%