Mark the correct alternative in the following:

If the ratio of base radius and height of a cone is 1 : 2 and percentage error in radius is λ%, then the error in its volume is:


given that the radius is half then the height of the cone so

Let h = 2r (where r is radius and h is height of the cone)


Volume of the cone = v



(because h = 2r )



Δv = 2πr2Δr


So finally ,



= 3×λ


= 3λ%

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