Mark the correct alternative in the following:

If f(x) = exsinx in [0, π], then c in Rolle’s theorem is


As, f(x) = ex Sin x


Differentiating the function with respect to ‘x’,


f’(x) = ex Cos x + Sin x ex


f’(c) = ec Cos c + Sin c ec


As, ex Cos x is continuous and derivable in R.


it is contionous on and derivable on .


f(0) = e0 Sin (0)


= 0





f’(c) = 0






ec Cos c + Sin c ec = 0


ec (Cos c + Sin c) = 0


Cos c + Sin c = 0 -------- (i)


Cos c = - Sin c









c = Є (0, )


Hence, Option (D) is the answer.

1