If we consider the above figure as for getting it,their will be many points on the curve.

If the normal to the point B passes through the point(2,1) then point B will be the point having nearest distance from point (2,1).

Let B(x,y)

=

slope at the point B is (2/y) and normal’s slope will be m=(–y/2) so by point slope formula.

⇒ (y-y1)=m(x-x1);(x1=2,y1=1)

⇒ (y-1)=(-y/2)(x-2)

⇒2y-2=-xy+2y

⇒xy=2;

⇒from above to equations

⇒y=2 and x=1

so the nearest point is (1,2).

Option(B)