Write the point where (
) =
e
attains minimum value.
Let f (x)= x loge x. Clearly f (x) is only defined for x >0.
For minimum value; f’(x)=0 and f’’(x)>0.
f’(x)= 1+lnx
⇒ x=1/e
f’’(x)= 1/x, Clearly f’’(x)>0 for all x. So only minima is defined.
So, minima of f (x) is at x = 1/e