#Mark the correct alternative in each of the following

If then its maximum value is


achieves it’s maximum value when g(x)=4x2+2x+1 achieves it’s minimum value.

Differentiating g(x) with respect to x, we get


g’(x)=8x+2


Differentiating g’(x) with respect to x, we get


g’’(x)=8


For minima at x=c, g’(c)=0 and g’’(c)>0


g’(x)=0



Hence is a point of minima for g(x) and is the minimum value of g(x).


Hence the maximum value of

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