#Mark the correct alternative in each of the following
If then its maximum value is
achieves it’s maximum value when g(x)=4x2+2x+1 achieves it’s minimum value.
Differentiating g(x) with respect to x, we get
g’(x)=8x+2
Differentiating g’(x) with respect to x, we get
g’’(x)=8
For minima at x=c, g’(c)=0 and g’’(c)>0
g’(x)=0 ⇒
Hence is a point of minima for g(x) and
is the minimum value of g(x).
Hence the maximum value of