#Mark the correct alternative in each of the following

f(x) = 1 + 2 sinx + 3cos2 x, 0 ≤ x ≤ is


f(x)=1+2sinx+3cos2x,

Differentiating f(x) with respect to x, we get


f’(x)=2cosx-6cosxsinx


Also, differentiating f’(x) with respect to x, we get


f’’(x)=-2sinx-6cos2x+6sin2x=-2sinx+12sin2x-6 (Since sin2x+cos2x=1)


For extreme points, f’(x)=0


2cosx(1-3sinx)=0 or or


and


Hence, is a point of minima and is a point of maxima.

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