#Mark the correct alternative in each of the following
f(x) = 1 + 2 sinx + 3cos2 x, 0 ≤ x ≤ is
f(x)=1+2sinx+3cos2x,
Differentiating f(x) with respect to x, we get
f’(x)=2cosx-6cosxsinx
Also, differentiating f’(x) with respect to x, we get
f’’(x)=-2sinx-6cos2x+6sin2x=-2sinx+12sin2x-6 (Since sin2x+cos2x=1)
For extreme points, f’(x)=0
⇒ 2cosx(1-3sinx)=0 or or
and
Hence, is a point of minima and
is a point of maxima.