#Mark the correct alternative in each of the following
The maximum value of 
on [–1, 1] is
Differentiating f(x) with respect to x, we get
Since 4-x2>0 ∀ x∈[-1,1] and (4+x+x2)2>0 ∀ x∈R
Therefore, f’(x)>0 ∀ x∈[-1,1]
Hence, f(x) is increasing in [-1,1] and therefore the maximum value of f(x) occurs at x=1 and 
1