#Mark the correct alternative in each of the following
The minimum value of the function f(x) = 2x3 – 21x2 + 36x – 20 is
f(x) = 2x3 – 21x2 + 36x – 20
Differentiating f(x) with respect to x, we get
f’(x)= 6x2 - 42x + 36=6(x-1)(x-6)
Differentiating f’(x) with respect to x, we get
f’’(x)=12x-42
for minima at x=c, f’(c)=0 and f’’(c)>0
f’(x)=0 ⇒ x=1 or x=6
f’’(1)=-30<0 and f’’(6)=30>0
Hence, x=6 is the point of minima for f(x) and f(6)=-128 is the local minimum value of f(x).