If 
then write the value f(x).
Given, 
It is clearly of the form,
By comparison, f(x)=1+
; fI(x)=
= ex (1+tanx) +C
Therefore, the value of f(x)=1+tanx
1
If then write the value f(x).
Given,
It is clearly of the form,
By comparison, f(x)=1+ ; fI(x)=
= ex (1+tanx) +C
Therefore, the value of f(x)=1+tanx