above equation can we solve by the formula of (1+cot 2 x=cosec 2 x) I = ∫ cosec 4 2x dx = ∫cosec 2 2x (1+cot 2 2x) dx = ∫ cosec 2 2x dx + ∫cosec 2 2x cot 2 2x dx Let us consider that cot2x=t then -2.cosec 2 2xdx=dt

Evaluate

above equation can we solve by the formula of (1+cot²x=cosec²x)

_{I = ∫ cosec}⁴2x dx

_{= ∫cosec}²2x (1+cot²2x) dx

_{= ∫ cosec}²2x dx + ∫cosec²2x cot²2x dx

Let us consider that cot2x=t then -2.cosec²2xdx=dt