Evaluate

Given,

Now, 3x2+13x-10


= 3x2+15x-2x-10


= 3x(x+5)-2(x-5)


= (x-5) (3x-2)



1 A (3x-2) + B(x+5)


Equating ‘x’ coeff: -


0=3A+B


B=-3A


Equating constant:-


1=-2A+5B


1=-2A+5(-3A)


1=-2A-15A


1=-17A









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