The area enclosed between the curves y =log e (x + e), x = log e and the x-axis is

Question

Philoid · Accepted Answer

y =log_e (x + e) and x = log_e look like –

The curves intersect at (0, 1)

(Putting x = 0 in the 2 curves, y = log_e(e) = 1 and 0 = log_e(1/y),

i.e., y = 1/e⁰ = 1)

So, bounds are x = 1 – e to x = 0 for the first curve and then x = 0 to apparently x = ∞ for the second curve.

Therefore,

(Ans)