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The area bounded by the y-axis, y = cos x and y = sin x when 0 ≤ x ≤ π/2 is
The area we want is –
We’ll integrate w.r.t y, since area is enclosed by curves and y – axis.
Intersection point is at x = π/4, i.e., y = 1/√2
So, area A enclosed is –
A =
Using Integration by parts –
A =
Putting u = 1 – y2
We get du = -2y dy
A =
=
=
= π/4√2 + 1/√2 – 0 – 1 + 0 – 0 - π/4√2 + 1/√2
= √2 - 1 (Ans)