Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is



The area we need is –



This area A = area of quadrant OAB – area of triangle OAB


= πr2/4 – � x base x height


= π x 22/4 – � x 2 x 2


= π – 2 (Ans)

1