Area lying between the curves y2 = 4x and y = 2x is

At the points of intersection,


x = y2/4 = y/2


Or, y2 = 2y


i.e., y2 – 2y = 0


i.e., y(y – 2) = 0


i.e., y = 0, 2


So, area A enclosed is –


A =


=




(Ans)

1