Area lying between the curves y2 = 4x and y = 2x is
At the points of intersection,
x = y2/4 = y/2
Or, y2 = 2y
i.e., y2 – 2y = 0
i.e., y(y – 2) = 0
i.e., y = 0, 2
So, area A enclosed is –
A =
=
(Ans)