RD Sharma - Mathematics (Volume 2)

Book: RD Sharma - Mathematics (Volume 2)

Chapter: 21. Areas of Bounded Regions

Subject: Maths - Class 12th

Q. No. 32 of MCQ

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32

Area lying in first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2, is

The part of the circle x2 + y2 = 4 in between x = 0 and x = 2 is the semicircle to the right of the y – axis.


And the part of this semicircle in the first quadrant is a quadrant of the circle.


So, area A of the portion is basically the area of a quadrant of the circle.


A = πr2/4


= π × 22/4


= π (Ans)

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