Area lying in first quadrant and bounded by the circle x2 + y2 = 4 and the lines x = 0 and x = 2, is
The part of the circle x2 + y2 = 4 in between x = 0 and x = 2 is the semicircle to the right of the y – axis.
And the part of this semicircle in the first quadrant is a quadrant of the circle.
So, area A of the portion is basically the area of a quadrant of the circle.
∴ A = πr2/4
= π × 22/4
= π (Ans)