Mark the correct alternative in each of the following:
The solution of the differential equation with y(1) = 1 is given by
By the method of variable separable
Integrating both sides we get,
⇒log √y=log C. x-1
∵ log a + log b = log ab
Squaring both sides, we get,
Now the given condition is y(1) = 1
⇒C=1
∴ The solution of the differential equation is
=(A)