Mark the correct alternative in each of the following:
The solution of the differential equation
with y(1) = 1 is given by
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By the method of variable separable
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Integrating both sides we get,
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⇒log √y=log C. x-1
∵ log a + log b = log ab
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Squaring both sides, we get,
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Now the given condition is y(1) = 1
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⇒C=1
∴ The solution of the differential equation is
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=(A)