By the method of variable separable we get,

Integrating both sides,

∵ log a + log b = log ab

Squaring both sides, we get,

Where A = C²

Since it is the form of (y – k)² = 4p(x – h) which represents parabolas.

i.e. (y – (-3))² = A(x – 0)

∴ The solution of the differential equation represents parabolas = (D)