Mark the correct alternative in each of the following:

The differential equation which represents the family of curves y = eCx is


y = eCx

Taking log both sides we get,


log y = log eCx


log y = Cx log e log ax = x log a


log y = Cx --(1) log e = 1


Differentiate w.r.t x we get,



Put value of C in (1) we get,




Which is y ln y = xy1 = (D)

1