Mark the correct alternative in each of the following:
If in a Δ ABC, A ≡ (0, 0), B ≡ (3, 3, √3), C ≡ (–3, √3, 3), then the vector of magnitude units directed along AO, where O is the circumcentre of Δ ABC is
Slope of a line joining two points
Slope of AC
Slope of AB
Product of Slopes (AC AB) =
= -1
As the Product of Slopes (AC AB) = -1, so AC ⟘ AB, ie..,
CAB = 90°.
Circumcentre (O) of Triangle ABC = Mid-Point of BC
Mid-Point of BC =
Now,
Unit Vector
Vector along , whose magnitude is
Option (A) is the answer.