Write the length (magnitude) of a vector whose projections on the coordinate axes are 12, 3 and 4 units.
Since Lx=12, Ly=3 and Lz=4 are given, we can find out L by
L2= Lx2+Ly2+Lz2
=122+32+42
=144+9+16=169
Hence L=13 units.