Mark the correct alternative in each of the following:
From a set of 100 cards numbered 1 to 100, one card is drawn at random. The probability that the number obtained on the card is divisible by 6 or 8 but not by 24 is
No. divisible by 6 between 1-100 (A) = 16
No. divisible by 8 between 1-100 (B) = 12
No. divisible by 6 and 8 between 1-100 (C) = 4
No. divisible by 24 between 1-100 (D) = 4
P(No. divisible by 6 or 8) = P(A) + P(B) – P(C)
P(divisible by 6 or 8 but not by 24) = P(divisible by 6 or 8) – P(divisible by 24)
1