Mark the correct alternative in each of the following:

A bag contains 5 red and 3 blue balls. If 3 balls are drawn at random without replacement, then the probability that exactly two of the three balls were red, the first ball being red, is


C. 15/28 D. 5/28


Total Red Balls = 5


Total Blue Balls = 3


M = Event getting Red ball


N = Event getting Blue ball


Now,


P(Getting exactly 2 red balls of 3 balls, the first ball being red)


(Since 1st ball is already red, P(red ball) = and so on..)



1