Mark the correct alternative in each of the following:
Three person, A, B and C fire a target in turn starting with A. Their probabilities of hitting the target are 0.4, 0.3 and 0.2 respectively. The probability of two hits is
A = Event of Person A hitting the target.
P(A) = 0.4
P = 1 – P(A) = 1 – 0.4
P = 0.6 → (1)
B = Event of Person B hitting the target.
P(B) = 0.3
P = 1 – P(B) = 1 – 0.3
P = 0.7 → (2)
C = Event of Person C hitting the target.
P(C) = 0.2
P = 1 – P(C) = 1 – 0.2
P = 0.8 → (3)
Now then,
= 0.4 × 0.3 × 0.8 + 0.4 × 0.7 × 0.2 + 0.6 × 0.3 × 0.2
= 0.096 + 0.056 + 0.036
= 0.188