Construct a 3 × 2 matrix whose elements are given by aij = (2i – j).

Given: aij = (2i – j)


Now, a11 = (2 × 1 – 1) = 2 – 1 = 1


a12 = 2 × 1 – 2 = 2 – 2 = 0


a21 = 2 × 2 – 1 = 4 – 1 = 3


a22 = 2 × 2 – 2 = 4 – 2 = 2


a31 = 2 × 3 – 1 = 6 – 1 = 5


a32 = 2 × 3 – 2 = 6 – 2 = 4


Therefore,



1