If A = diag [2, -5, 9], B = diag [-3, 7, 14] and C = diag [4, -6, 3], find:
(i) A + 2B
(ii)B + C – A
If Z = diag[a,b,c], then we can write it as
So, A+2B
=diag[4,9,37]
Conclusion: A + 2B = diag[4,9,37]
(Given answer is wrong)
ii. B + C – A
If Z = diag[a,b,c], then we can write it as
B+C-A
= diag[-1,6,8]
Conclusion: B+C-A = diag[-1,6,8]
iii. 2A + B – 5C
If Z = diag[a,b,c], then we can write it as
2A+B-5C
= diag[-19,27,17]
Conclusion: 2A + B – 5C = diag[-19,27,17]
(Given answer is wrong)