Let f : R → R be defined by
Find (i) f(2) (ii) f(4) (iii) f( - 1) (iv) f( - 3).
i)f(2)
Since f(x) = x2 - 2 , when x = 2
∴ f(2) = (2)2 - 2 = 4 - 2 = 2
∴f(2) = 2
ii)f(4)
Since f(x) = 3x - 1 , when x = 4
∴f(4) = (3×4) - 1 = 12 - 1 = 11
∴f(4) = 11
iii)f( - 1)
Since f(x) = x2 - 2 , when x = - 1
∴ f( - 1) = ( - 1)2 - 2 = 1 - 2 = - 1
∴f( - 1) = - 1
iv)f( - 3)
Since f(x) = 2x + 3 , when x = - 3
∴f( - 3) = 2×( - 3) + 3 = - 6 + 3 = - 3
∴f( - 3) = - 3