If A=is singular then k=?

When a given matrix is singular then the given matrix determinant is 0.


= 0


Given,


A=


= 0


1(-4k + 6) –k(-12 + 4) +3 (9 -2k)= 0


-4k + 6 +12k -4k + 27 -6k = 0


-2k +33 = 0


k = .

1