Given: sec x = -2

Given that:

So, x lies in III^rd Quadrant. So, sin and cos will be negative but tan will be positive.

Now, we know that

Putting the values, we get

…(i)

We know that,

cos² x + sin² x = 1

Putting the values, we get

[given]

Since, x in III^rd quadrant and sinx is negative in III^rd quadrant

Now,

Putting the values, we get

=√3

Now,

Putting the values, we get

Now,

Putting the values, we get

Hence, the values of other trigonometric Functions are: