Prove that

(i)


(ii)


(i)sin(50° + θ)cos(20° + θ) - cos(50° + θ)sin(20° + θ)

= sin(50° + θ - (20° + θ))(using sin(A - B) = sinAcosB - cosAsinB)


= sin(50° + θ - 20° - θ)


= sin30°



(ii)cos(70° + θ)cos(10° + θ) + sin(70° + θ)sin(10° + θ)


= cos(70° + θ - (10° + θ))(using cos(A - B) = cosAcosB + sinAsinB)


= cos(70° + θ - 10° - θ)


= cos60°



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