Prove that

(i)


(ii)


(iii)


(i) cos150

Sin150


Cos150 - sin150





(ii)cot105° - tan105° = cot(180° - 75°) - tan(180° - 75°)


(II quadrant tanx is negative and cotx as well)


= - cot75° - ( - tan75°)


= tan75° - cot75°


Tan75° =


(using sin(90° - x) = - cosx and cos(90° - x) = sinx)



Cot75° =


Cot105° - tan105° =



(iii)


(II quadrant tanx negative)


- tan45° = - 1


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