If A + B + C = π, prove that
cos2 A + cos2 B + cos2 C = 1 – 2cos A cos B cos C
= cos2 A + cos2 B + cos2 C
Using formula ,
Using ,
Using , since A + B + C = π
And, cos(π – A ) = -cosA
Using cos2A = 2cos2A -1
= 1 + cos2A – cosAcos(B-C)
= 1 + cosA{cosA - cos(B-C)}
Using ,
Since , A + B + C = π
= 1 - 2cosAcosCcosC
= R.H.S