If A + B + C = π, prove that

cos2 A + cos2 B + cos2 C = 1 – 2cos A cos B cos C


= cos2 A + cos2 B + cos2 C


Using formula ,






Using ,





Using , since A + B + C = π



And, cos(π – A ) = -cosA




Using cos2A = 2cos2A -1




= 1 + cos2A – cosAcos(B-C)


= 1 + cosA{cosA - cos(B-C)}


Using ,




Since , A + B + C = π




= 1 - 2cosAcosCcosC


= R.H.S


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