As angle is given so we have to find slope first give by m = tanθ

m = tan150°

(tan (180° - θ) is in II quadrant, tanx is negative)

Now the line is passing through the point (3, - 5).Using the slope - intercept form of the equation of the line, we will find the intercept

y = mx + c ……………….(1)

Putting the value of c in equation (1),we have