Find the equation of the line passing through the point P( - 3, 5) and perpendicular to the line passing through the points A(2, 5) and B( - 3, 6)

As two points passing through line perpendicular to the line are given, we will calculate slope using two points. Let slopes of the two lines be m1 and m2.



Now the slope of the equation can be found using




Using slope - intercept form we will find intercept for line passing through ( - 3, 5)


y = mx + c ………………….(1)


5 = 5( - 3) + c


c = 5 + 15


c = 20


Putting value in equation (1)


y = 5x + 20


5x - y + 20 = 0


So, the required equation of line 5x - y + 20 = 0.


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