Find the equations of the altitudes of a ΔABC, whose vertices are A(2, - 2), B(1, 1) and C( - 1, 0).

Altitude: A line drawn from the vertex that meets the opposite side at right angles. It determines the height of the triangle.

In triangle ABC, let the altitudes from vertices A, B and C are AL, BM and CN on sides BC,AC and AB respectively.


Now we will find slope of sides and using the relation between the slopes of perpendicular lines i.e. m1.m2 = - 1 we will find the slopes of altitudes.












Now equation of altitudes using two point form


For altitude AL,



y - ( - 2) = - 2(x - 2)


y + 2 + 2x - 4 = 0


2x + y - 2 = 0


For altitude BM,



y - 1 = - 1(x - 1)


y - 1 + x - 1 = 0


x + y - 2 = 0


For altitude CN,




3y = x + 1


x - 3y + 1 = 0


So, the required equations of altitudes are for AL: 2x + y - 2 = 0


For BM: x + y - 2 = 0


For CN: x - 3y + 1 = 0


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