Find the equations of the altitudes of a ΔABC, whose vertices are A(2, - 2), B(1, 1) and C( - 1, 0).
Altitude: A line drawn from the vertex that meets the opposite side at right angles. It determines the height of the triangle.
In triangle ABC, let the altitudes from vertices A, B and C are AL, BM and CN on sides BC,AC and AB respectively.
Now we will find slope of sides and using the relation between the slopes of perpendicular lines i.e. m1.m2 = - 1 we will find the slopes of altitudes.
Now equation of altitudes using two point form
For altitude AL,
y - ( - 2) = - 2(x - 2)
y + 2 + 2x - 4 = 0
2x + y - 2 = 0
For altitude BM,
y - 1 = - 1(x - 1)
y - 1 + x - 1 = 0
x + y - 2 = 0
For altitude CN,
3y = x + 1
x - 3y + 1 = 0
So, the required equations of altitudes are for AL: 2x + y - 2 = 0
For BM: x + y - 2 = 0
For CN: x - 3y + 1 = 0