The vertices of a quadrilateral are A(-4, -2), B(2, 6), C(8, 5) and D(9, -7). Using slopes, show that the midpoints of the sides of the quad. ABCD from a parallelogram.
The vertices of the given quadrilateral are A(-4,-2) B(2, 6), C(8, 5) and D(9, -7)
The mid point of a line A(x1,y1) and B(x2,y2) is found out by
Now midpoint of AB =
The midpoint of BC =
The midpoint of CD =
Midpoint of DA =
So now we have four points
P(-1,2),Q(5,5.5),R(8.5,-1),S(2.5,-4.5)
Slope of PQ =
Slope of QR =
Slope of RS =
Slope of SP =
Now we can observe that slope of PQ = RS and slope of QR = SP
Which shows that line PQ is parallel to RS and line QR is parallel to SP
Also, the product of two adjacent lines is not equal to -1
Therefore PQRS is a parallelogram.