Find the equation of the parabola with vertex at the origin, passing through the point P(5, 2) and symmetric with respect to the y-axis.
The equation of a parabola with vertex at the origin and symmetric about the y-axis is
x2 = 4ay
Since point P(5,2) passes through above parabola we can write,
52 = 4a(2)
• 25 = 8a
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Therefore, the equation of a parabola is
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• 
• 2x2 = 25y
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