Find the derivation of each of the following from the first principle:
3x2 + 2x – 5
Let f(x) = 3x2 + 2x – 5
We need to find the derivative of f(x) i.e. f’(x)
We know that,
…(i)
f(x) = 3x2 + 2x – 5
f(x + h) = 3(x + h)2 + 2(x + h) – 5
= 3(x2 + h2 + 2xh) + 2x + 2h – 5
[∵(a + b)2 = a2 + b2 + 2ab]
= 3x2 + 3h2 + 6xh + 2x + 2h – 5
Putting values in (i), we get
Putting h = 0, we get
f’(x) = 3(0) + 6x + 2
= 6x + 2
Hence, f’(x) = 6x + 2