Find the derivation of each of the following from the first principle:
tan (3x + 1)
Let f(x) = tan (3x + 1)
We need to find the derivative of f(x) i.e. f’(x)
We know that,
…(i)
f(x) = tan (3x + 1)
f(x + h) = tan [3(x + h) + 1]
Putting values in (i), we get
Using the formula:
Putting h = 0, we get
= 3sec2(3x+ 1)
Hence, f’(x) = 3sec2(3x+ 1)