Find the derivation of each of the following from the first principle:

tan (3x + 1)


Let f(x) = tan (3x + 1)

We need to find the derivative of f(x) i.e. f’(x)


We know that,


…(i)


f(x) = tan (3x + 1)


f(x + h) = tan [3(x + h) + 1]


Putting values in (i), we get



Using the formula:










Putting h = 0, we get





= 3sec2(3x+ 1)


Hence, f’(x) = 3sec2(3x+ 1)


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